Karnan posted an Question
December 12, 2020 • 17:12 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Among the following reactions, which form salicylic acid (after acidification): a) oh +chcl +naoh b) oh +cc4+naoh oh +co+naoh d) cooh +naoh

Among the following reactions, which form salicylic acid (after acidification): a) OH +CHCl +NaOH b) OH +CC4+NaOH OH +CO+NaOH d) COOH +NaOH

3 Answer(s) Answer Now
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  • comment-profile-img>
    Dinesh khalmaniya 1

    B and C both are correct. Explanation - A and B are reimer tieman reactions. A gives salicyldehyde while B gives salicylic acid. C is kolbe's reaction and gives salicylic acid. while D gives salt with base

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    got it??

  • comment-profile-img>
    Priyanshu kumar best-answer

    B and C both are correct way B is riemer tiemann reaction and C is kolbe schmitt reaction. A is riemar tiemann reaction in which salicylaldehyde is formed and in D sodium benzoate salt is formed

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    any doubt aswin?

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    Lingareddy 1 best-answer

    b also salicylic acid formation. but it directly obtained

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  • comment-profile-img>
    Ashutosh singh

    I guess B is the correct pathway to form salicylic acid.

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