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An isolated ideal gas of one mole is made to free expansion, twice of its volume. change in entropy in si unit is ?
An isolated ideal gas of one mole is made to free expansion, twice of its volume. Change in entropy in SI unit is ?
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Dr suman 1
Change in entropy = ΔS = Nk × ln(Vf/Vi) N = number of atoms (1 mole equals Avogadro’s number) = 6.022 × 10^23 k = Boltzmann constant = 1.3806 × 10^-23 Vf = final volume = 2 Vi = initial volume = 1 Then, ΔS = Nk × ln(Vf/Vi) = (6.022 × 10^23) × (1.3806× 10^-23) × ln(2/1) = 5.763
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free expansion = adiabatic process. Am I right ??? then ∆s = 0
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Kapil prajapat![best-answer]()
free expansion means temperature is same not adiabatic.