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Simun Mishra posted an Question

May 11, 2020 • 14:36 pm

30 points

IIT JAM
Chemistry (CY)

Arrange the following in decreasing order of their bond order. ...and how to know the total no of e in each compounds

2 Answer(s)

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Suman Kumar

Mo of CO is little complex but if you want then i can send
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send this
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Dinesh khalmaniya 1

MOT of NO+ and NO
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Dinesh khalmaniya 1 Best Answer

check it for your clarification
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Dinesh khalmaniya 1

remaining q3
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NO has total 2 equal to 15 so correct it
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give one example of when all the surrounding atoms are same and when not same
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why here No+ = 8- 2 ÷ 2
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you can use short trick as NO+ = 7+8-1 = 14e so BO = 3 or you can solve using bond order formula but you can solve it if you know MOT diagram of NO. so im sending you MOT of NO+ please check it
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ok
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here No is 3.5 ..bond order
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NO bond order is 2.5 not 3.5
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but the total no of e in No is 15 ...and the bond order is 3.5
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ok ok sry ........its clear ....
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Suman Kumar

I have provided the answer
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For CO when you will see the mo in that that non bonding mo has little anti bonding character that's why co+ bond order increases. These are experimentally found
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sorry but ...I can't understand ....this ....
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the mot structure ...and ur handwriting is no ...clear ....so ..
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Dinesh khalmaniya 1

check it
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can u pls give example of the 2 point about resonance
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wait.
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here CO+ is ..2.5 according to mot total no of e is 6+8 =14 and due to + charge it will be 14-1 =13 so 2.5..?
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