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Chandan panigrahi Asked a Question
October 10, 2020 9:10 ampts 30 pts
  • IIT JAM
  • Chemistry (CY)

Arrange the following in decreasing order of their stability ? os 1. ch-c-oh e> ch- oh > ch-c-0-h ch-c-oh (i) (ii) (iv)

Arrange the following in decreasing order of their stability ? Os 1. CH-C-OH e> CH- OH > CH-C-0-H CH-C-OH (i) (ii) (iv)
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  • Priyanshu kumar thankyou
    I>3>2>4 In 2 and 4 no of covalent bond is 4 and in 1st and 3rd no of covalent bond is 5.. positive charge on electronegative atom is less stable
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    Priyanshu kumar
    Now arrange this by considering all these
  • Dinesh khalmaniya Best Answer
    i>iii>ii>iv Follow the below order given
    • cropped2524455043015354211.jpg
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    Chandan panigrahi
    sir how the 2nd one is more stable than 4th one as in 4th case thare is octet complete but in 2nd case thare is no octet completed
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