Dhivya Dharshini Asked a Question
October 22, 2020 5:11 pmpts 30 pts
Assertion (P) : sin |x| is differentiable at x = 0 Reason (Q): sin x is continuous at x = 0. Which of the following is true? (A) Both P and Q are true and Q is the correct explanation for P (B) Both P and Q are true but Q is not the correct but CQ is false (C) P is true but Q is false (D) P is false but Q is true
  • 2 Answer(s)
  • 0 Likes
  • 2 Comments
  • Shares
  • Mahendra devanda thankyou
    option D is true . answer is attached below
    • cropped4555367335654390035.jpg
    • cropped2769233316766815710.jpg
    Likes(0) Reply(0)
  • Deepak singh Best Answer
    clearly sinx is continuous by graph of sinx and sin|x| is not differentiable at 0( see attached ) , so option d is true ..
    • cropped160299128513106157.jpg
    Likes(0) Reply(0)