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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Abhijeet Gaurav
Number of gamete possible in a parent is 2^n (where n- number of heterozygous allele in parent genotype) number of zygotes possible are (gamete)X(gamete) The number of gamete formation possible by parent 1 (AaBBCcDd) - 2^3 = 8 (n=number of heterozygous allele = 3) The number of gamete formation possible by parent 2 (AAbbCcDD) - 2^1 = 2 (n=number of heterozygous allele = 1) So, the number of zygotes possible are = gamete of parent 1 X gamete of parent 2 = 8 X 2 = 16 So, the correct answer to the question is '16'