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Aparna Singh posted an Question
June 05, 2021 • 01:44 am 30 points
  • IIT JAM
  • Biotechnology (BT)

Assuming the comparable chromosomes in different individuals are genetically dissimilar because of different alleles. how many unique zygotic combinations are

Assuming the comparable chromosomes in different individuals are genetically dissimilar because of different alleles. How many unique zygotic combinations are possible following fertilization in an organism where n = 3 (Assuming that no crossing over occurs)? a. 8 b. 16 C. 64 d. 216

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  • Abhijeet Gaurav best-answer

    Number of gamete possible in a parent is 2^n (where n- number of heterozygous allele in parent genotype) number of zygotes possible are (gamete)X(gamete) The number of gamete formation possible by parent 1 (AaBBCcDd) - 2^3 = 8 (n=number of heterozygous allele = 3) The number of gamete formation possible by parent 2 (AAbbCcDD) - 2^1 = 2 (n=number of heterozygous allele = 1) So, the number of zygotes possible are = gamete of parent 1 X gamete of parent 2 = 8 X 2 = 16 So, the correct answer to the question is '16'

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