Sanjana posted an Question
July 21, 2020 • 17:12 pm 50 points
  • IIT JAM
  • Chemistry (CY)

At 700 k, the equilibrium constant kp for the reaction, 2so3(g) 2so2(g) + 2(8) is 1.80 x 10- kpa. the value of ke in mol/l at the same temperature is? give the

At 700 K, the equilibrium constant kp for the reaction, 2SO3(g) 2SO2(g) + 2(8) is 1.80 x 10- KPa. The value of Ke in mol/L at the same temperature is? Give the answer in terms of 10- mol/L

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