IIT JAM
profile-img
Imdadul haque Asked a Question
September 20, 2020 6:53 pmpts 30 pts
  • IIT JAM
  • Chemistry (CY)

At constant pressure, the presence of argon at the equilibrium of na(g)+3h(g)2nh(8) will (a) reduce the formation of nh3 (b) increase the formation of nh ()redu

At constant pressure, the presence of argon at the equilibrium of Na(g)+3H(g)2NH(8) will (a) reduce the formation of NH3 (b) increase the formation of NH ()reduce the formation of H, (d) increase the formation of both N, and H2
  • 2 Answer(s)
Answer Now
  • 0 Likes
  • 2 Comments
  • Shares
  • Priyanshu kumar thankyou
    Hope this will helps you😊
    Likes(0) Reply(0)
  • Priyanshu kumar Best Answer
    The reaction for the formation of ammonia is N2​(g)+3H2​(g)⇔2NH3​(g). The forward reaction occurs with a decrease in the number of moles from 4 to 2. Also, the reverse reaction occ...
    Show more
    Likes(0) Reply(3)
    Priyanshu kumar
    Option A is correct
How Eduncle Helps You ?
StudentTutorInstitutionApp
Help
FAQsPayment TermsRefund PolicyAsk Support
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com