Sarath Asked a Question
November 1, 2021 7:35 pmpts 30 pts
(B) The given equation can be rewritten as [D+(g/eje = 0, where D d/dt The auxiliary equation is m? + (g/e) = 0 :om. m2- (g/e) or m = t v(g/e)ji. The solution of the given, differential equation is e C, cos {V(g/) t+C) where C,, C, are arbitrary constants ) and de/dt=- V(g/e)C, sin fV(g/e) +C} where t= 0, 0 = 0, and de/dt = 0 (given so from () and (i) we get 6=C, cos C, and 0 = -V(g/e)C, sin C From these we have sin C, = 0 and C, # 0 and so C, = From (), the required solution is 0 , cos {(V(g/e) t)}
  • 1 Answer(s)
  • 0 Likes
  • 2 Comments
  • Shares
  • Ravi bhushan thankyou
    Here is the detailed solution.
    • cropped590391459174124448.jpg
    Likes(0) Reply(4)
    Sarath
    please explain why u write theta =C1 cos {√g/l+ C2 }
  • Sarath
    for imaginary part what is c.f formula
    Likes(0) Reply(0)
Head Office :
MPA 44, 2nd floor, Rangbari Main Road,
Mahaveer Nagar II, Kota (Raj.) – 324005

Corporate Office:
212, F-1, 2nd Floor, Evershine Tower,
Amrapali Marg,
Vaishali Nagar, Jaipur (Raj.) – 302021

Mail: info@eduncle.com
All Rights Reserved © Eduncle.com