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Anushka Gupta posted an Question

August 10, 2020 • 16:47 pm

35 points

IIT JAM
Chemistry (CY)

Bde is promotional to bo how

bond dissociation energy is proportional to bond order how

2 Answer(s)

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Mayank

as bond order increases bond strength increases and no. of bonds are also increasing so more bde will required to break 2 or 3 bondso comparatively single bond
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ok i got it 😊
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Priyanshu kumar Best Answer

See when bond order increase....bond strength increases...so energy required to break the bond also increases...so we can say Bond dissociation energy is directly proportional to bond order
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As in single bond Bond order is 1 in double bond Bond order is 2...so strength of double bond is strong...so it requires more bond dissociation enthalpy
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got it anushka??
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If you have any doubt...please ask😊
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but pie bond is present in double nd triple bond so bond should be weak
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Another criteria the more bonding electrons are to be found the more stronger the bond
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sharing of electrons is more in triple bond then double then single
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so strong bond...with increases in bond order
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ok i got it😊
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😊👍
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Suman Kumar

Yes Anuska Bond dissociation energy is directly proportional to bond order.
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What does bond order signify?
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Highly the bond order more stronger will be the bond.
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More stronger the bond more we need more energy to break the bond i.e higher bond dissociation energy.
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bur pie bond is also present double nd triple bond so bond should be weak
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See we say pi bond are weak. But we say this comparing with sigma bond.
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Pi bond are weak in comparison with sigma bond.
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N2>O2>F2. This is the order for bond dissociation energy. As N2 has bond order 3
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ok i got it 😊
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Thankyou Anushka 😊🙏
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