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Divya posted an Question
September 06, 2020 • 00:52 am 30 points
  • IIT JAM
  • Chemistry (CY)

Bond order

Sir for this compound I got bond order value 2 but its value is 1.6 .plz explain this sir

2 Answer(s) Answer Now
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    Dinesh khalmaniya 1 best-answer

    counts the total bonds between C-Cl here total bonds are 8. and devide it by total RS here it is 5 so BO= 8/5 = 1.6

    images (56).jpeg
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    got it??

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    ask if any doubt??

  • comment-profile-img>
    Divya Penumarthi

    sir I have drawn

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    check and coubt bond between carbon and chlorine in all the resonating structures

  • comment-profile-img>
    Priyanshu kumar Best Answer

    First draw resonating structure of chlorobenzene

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    total bond between carbon and chlorine in all resonating structure=8

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    and total resonating structure =5

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    Bond order=8/5=1.6

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    draw resonating structure and send me divya

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    you clearly get this

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    see

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    any doubt you can ask me

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    sir once see this

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    count carbon and chlorine bonds

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    total 8 bonds na

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    in all 5 resonating structure...and divide 8 by total resonating structure =5...8/5=1.6

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    now got?

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    yes sir got it

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    waise resonating structure aapne galat bnaya hai

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    see my attached image

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    bdw you got this concept na??

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    sir what is that

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    in hindi

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    means you draw wrong resonating structure...check my attached image

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    sorry sir in a hurry

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    I have drawn wrong

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    it's okay....in hurry you did mistake....bdw got this concept .?

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    thank you sir for rectifying . sir can you send me any link regarding Elements of symmetry .

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    okk sure

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    you want video in english??

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    yes sir

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    Okk let me check...bdw elements of symmetry for which chapter...means solid state,group theory or for stereochemistry?

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    stereochemistry sir

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    okk wait..let me check suitable video in english for u

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    whenever you sent the I will check sir

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    thank you so much sir

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    https://youtu.be/WdW0ctJT8hY short😊

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    https://youtu.be/hH2Zfucp0oo long😊

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    Thank you so much for your help sir

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    you're welcome divya😊

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