Shrigandha posted an Question
December 11, 2020 • 02:50 am 30 points
  • IIT JAM
  • Chemistry (CY)

C 1s2 2s2 2p2 excited state = 1s 2s1 2p3 spin multiplicity 2 11 +1 5 x5 +

C 1s2 2s2 2p2 eXcited state = 1s 2s1 2p3 Spin multiplicity 2 11 +1 5 x5 + I didn't understand how can we get 5

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    Dinesh khalmaniya 1

    spin multiplicity = 2S +1 here S = total clockwise electrons×1/2 - total anticlockwise electrons×1/2. each electron have value of s = 1/2

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