(c) calculate the enthalpy change for the process: h,o(1,-10°c) > h,o(s,-10°c) given, c, for water(liquid)= 75.4 jk' mol c, for ice(solid)= 37.2 jk mol" latent

(c) Calculate the enthalpy change for the process: H,O(1,-10°C) > H,O(s,-10°C) Given, C, for water(liquid)= 75.4 JK' mol C, for ice(solid)= 37.2 JK mol" Latent Heat of Fusion of ice at 0°C = 6.008 kJK°" mol