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Imdadul Haque posted an Question
January 14, 2021 • 11:54 am 30 points
  • IIT JAM
  • Chemistry (CY)

(c)n=2, he a doubly ionized lithium atom in an excited state (n = 6) emits a photon of energy 4.25 ev. what are the quantum number (n) and the energy (e) of the

(C)n=2, He A doubly ionized lithium atom in an excited state (n = 6) emits a photon of energy 4.25 eV. What are the quantum number (n) and the energy (E) of the final state? (d)n 3, LP (b) n=3, E=-13.6 eV (d)n-5, E-4.90 eV (a)n-2, E=-30.6 eVv (C)n-4, E=-7.65 eV

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