Adarsh Mishra posted an Question
November 07, 2020 • 23:48 pm 30 points
  • IIT JAM
  • Chemistry (CY)

(c)n=4, l=2, m, =-2, m,=+1/2 total number of possible shells in uranium atom (atomic no. z= 92) (d) n-4, l=0, m,=0, m, =+2 (a) 7 (b) 1 c)6 (d) none of these

(c)n=4, l=2, m, =-2, m,=+1/2 Total number of possible shells in uranium atom (atomic no. z= 92) (d) n-4, l=0, m,=0, m, =+2 (a) 7 (b) 1 C)6 (d) None of these

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  • Suman Kumar

    Number of shells is equal to the period . Option A is correct

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    Uranium is in 7th period

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    Dinesh khalmaniya 1 Best Answer

    option A Explanation- Total no. Of possible shells in any atom is infinite and in uranium 92 tje total no. Of electron occupied shells are 7 as its electronic configuration has 7 as the max value of the principle quanrum no. (n). configuration of Uranium. 1s22s22p23s23p64s23d104p65s24d105p66s24f145d106p67s25f4 ∴  Max shell =7

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