Adarsh Mishra posted an Question
July 24, 2020 • 16:35 pm 30 points
  • IIT JAM
  • Chemistry (CY)

(c r the decreasing order of stability of following cation is ch 15 ch2 ch ch2 ch3 ch3 chs (r) (s) (c) p r qs (d) s>r>qp ) (p) (a) p>q>r>s (b) p>sq>r

(C R The decreasing order of stability of following cation is CH 15 CH2 CH CH2 CH3 CH3 CHs (R) (S) (c) P R QS (d) S>R>QP ) (P) (a) P>Q>R>S (b) P>SQ>R

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  • Suman Kumar Best Answer

    See always give priority to resonance.

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    .Inductive effect depends on distance. Ortho position will have more inductive effect as it is closer to carbocation.

  • Suman Kumar best-answer

    Option C is correct

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    See Adarsh I have given the explanation

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    Now please ask anything if you don't get anything 🙏

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    Dinesh khalmaniya 1

    option c Explanation- CH3 group show +H effect on orho and para position and + I effect on meta position. both +H and +I effect increase the stability of carbocation. but +H effect stabilized more than +I effect

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    in case of ortho and para, both have same +H effect so we will check+I effect. Ortho CH3 group have less distance from carbocation than para so +I effect of ortho will more than para so ortho substitute benzyl carbocation is most stable than para. and then meta due to +I effect. and at last benzyl carbocation

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    got it??

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    please accept the answer 😊

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