profile-img
Imdadul Haque posted an Question
October 22, 2020 • 18:01 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Calculate the enthalpy change of 1 mole of reaction na(s)br,(0) nabr(s) in kcal given: ah (na)= 137 kj mole-; abond desociteon(br, (g)) = 144 kj mole- at eecton

Calculate the enthalpy change of 1 mole of reaction Na(s)Br,(0) NaBr(s) in kcal Given: AH (Na)= 137 kJ mole-; abond desociteon(Br, (g)) = 144 kJ mole- At eecton atno, (Br(g) =-325 kJ mole- AH naon(Na(g) = 496 kJ mole-; A NaBr) = +742

2 Answer(s) Answer Now
  • 0 Likes
  • 3 Comments
  • 0 Shares
  • comment-profile-img>
    Priyanshu kumar Best Answer

    check this

    cropped6497009257919734341.jpg
    eduncle-logo-app

    check this

    eduncle-logo-app

    please ask if any doubt

    eduncle-logo-app

    Sir 294 kahasee add hwa

    eduncle-logo-app

    ans kitna diya hua hai del H= - 367kj/mol?

    eduncle-logo-app

    -86.52 K cal/mole Ans haii

    eduncle-logo-app

    sahi hai ans.... kcal me change krne ke liye 4.2 se divide krna padega na

    eduncle-logo-app

    294 add nhi hoga...mistake hai wha pe

    eduncle-logo-app

    Okay sir thank you so much 😊

    eduncle-logo-app

    you're welcome 😊👍

    eduncle-logo-app

    Sir ,,,owha pe jo bond dissociation energy dya haii ow 2se divide hoga na ??

whatsapp-btn

Do You Want Better RANK in Your Exam?

Start Your Preparations with Eduncle’s FREE Study Material

  • Updated Syllabus, Paper Pattern & Full Exam Details
  • Sample Theory of Most Important Topic
  • Model Test Paper with Detailed Solutions
  • Last 5 Years Question Papers & Answers