Sayan posted an Question
May 26, 2020 • 19:24 pm 30 points
  • IIT JAM
  • Physics (PH)

Calculate the resistance of the circuit

3 Answer(s) Answer Now
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    Dhairya sharma Best Answer

    I understand that voltmeters are supposed to have high internal resistances so that they won't draw much current. However, they are being attached parallel to the resistor anyways and according to Kirchhoff' Law that means the voltage through both the resistor for which we are trying to measure the voltage and for the voltmeter, they will both experience the same voltage. Why does the voltmeter need to have a high internal resistance then. Isn't it redundant or unnecessary according to Kirchhoff law.

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    The voltmeter is connected parallel to a component of the circuit. This means the resistance (or impedance) of that part of the circuit is going to change, which in general changes the potential drop across the component. This effect will be larger if the voltmeter has lower resistance (to the point of completely ignoring the component if the voltmeter resistance goes to zero).

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    Thus, in order to get an accurate measure of what the potential would be without the voltmeter, it needs to have a high resistance.

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    if u have any doubt plz ask .

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    i hope u will get the solution.

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    you must know how to apply kvl law in loop.

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    good explanation ✌

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    tnq sir.

  • comment-profile-img>
    Ruby negi best-answer

    while doing this question, I kept in mind following things: 1) Current is same in series(that's why current through 2M-ohm is same through Rb) (2) formula of equivalent resistance in parallel case..

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    3) in overall circuit, I used KVL and then I found Rb.. (4) after Rb, I know the voltage across Rb so using this I can find the internal resistance of voltameter across Rb...

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    for any query ,you can ask...

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    see the attached page also..

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    try by urself too.. it's important..

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    ok😊

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