Suraj posted an Question
October 07, 2020 • 04:48 am 30 points
  • IIT JAM
  • Mathematical Statistics (MS)

Can you explain me that joint probality mass assignment table

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  • Kaushik gupta best-answer

    go through videos https://youtu.be/L0zWnBrjhng. and https://youtu.be/C8DLKwVRQeE

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    I just needed to know that there are 3 elements for each random variables and both the random variables are independent so the p(x=-1,y=-1) must be equal to (1/3)*(1/3)=1/9.isnt it right can you clarify me about this.

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    no this is incorrect . actually marginal probability given in the solution is also incorrect hope this will help u

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    p(x=-1,y=-1)=p(x=-1)*p(y=-1)=(1/6)*(1/2)=1/12

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    similarly find joint prob for every case

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    can you give a intitution on why P(x=-1)has 1/6 (please solve my doubt as I have recently developed intrest in math)

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    P(X=-1)=summation over y P(X=-1,Y=y)

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    So P(X=-1)=P(X=-1,Y=-1)+P(X=-1,Y=0)+P(X=-1,Y=1)

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    thus P(X=-1)=1/12+1/18+1/36=1/6

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    similarly obtain all marginal probabilities. note: column sum give u marginal prob of x and row sum give u marginal prob of y

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    see this attachment here I calculate all mariginal probabilities of x and y and also sum of marginal probability which is equal to 1

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    thanks bro

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    can you please explain me how you got that 1/12,1/18,1/36 values

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    it's given in question

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