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Reshav posted an Question
July 07, 2020 • 19:12 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Can you please explain the question and its solution explanation. an element x (atomic weight = 24 gm/mol) forms a face centered cubic lattice. if the edge leng

can you please explain the question and its solution explanation. An element X (atomic weight = 24 gm/mol) forms a face centered cubic lattice. If the edge length of the lattice is 4 x 10- cm and the observed density is 2.4 x 103 kg/m?, then the percentage Occupancy of lattice points by element X is: (Use N, = 6 x 1023): (A) (C) 6. (B) (D) 96 98 99.9 none of these

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    Dinesh khalmaniya 1 best-answer

    Percentage occupancy = 96 % ◆ Explanation - # Given - M = 24 g/mol = 24×10^-3 kg/mol a = 4×10^-8 cm = 4×10^-10 m d' = 2.4×10^3 kg/m^3 # Solution - For FCC lattice, density of unit cell is calculated as - d = Z.M / NA.a^3 d = (4 × 24×10^-3) / [6×10^23 × (4×10^-10)^3] d = 2.5×10^3 kg/m^3 Percentage occupancy in lattice structure will be - % Occupancy = observed density / calculated density × 100 % Occupancy = 2.4×10^3 / 2.5×10^3 × 100 % Occupancy = 96 % Hence, percentage occupancy lattice of element X is 96 %. Best luck

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