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Shanu posted an Question
June 04, 2020 • 23:41 pm 30 points
  • IIT JAM
  • Geology (GG)

Can you plz answer this question...

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    Sajan sarthak

    pressure at the depth of crust is 3 kbar and it's increasing 0.3 kbar per kilometre so (3/0.3. )=10km surface temperature=25 °c at the depth 275 so 275+25=300°c so gradient of temperature is 300°c/10km =30°c/km

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    Sajan sarthak

    pressure at the depth of crust is 3 kbar and it's increasing 0.3 kbar per kilometre so (3/0.3. )=10km surface temperature=25 °c at the depth 275 so 275+25=300°c so gradient of temperature is 300°c/10km =30°c/km

  • comment-profile-img>
    Sajan sarthak

    pressure at the depth of crust is 3 kbar and it's increasing 0.3 kbar per kilometre so (3/0.3. )=10km surface temperature=25 °c at the depth 275 so 275+25=300°c so gradient of temperature is 300°c/10km =30°c/km

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    Sajan sarthak Best Answer

    pressure at the depth of crust is 3 kbar and it's increasing 0.3 kbar per kilometre so (3/0.3. )=10km surface temperature=25 °c at the depth 275 so 275+25=300°c so gradient of temperature is 300°c/10km =30°c/km

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