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- IIT JAM
- Chemistry (CY)
Cerium (7-58) is an important member of lanthanides. which of the following statements about cerium is correct: (a) cerium v acts as an oxidizing agent. (b) the
Cerium (7-58) is an important member of lanthanides. Which of the following statements about cerium is correct: (a) Cerium V acts as an oxidizing agent. (b) The+ 4 oxidation state of cerium is not known in solution. (c) The+ 3 oxidation state is more stable that the + 4 state. (d) The common oxidation states of cerium are +3 and +4
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Priyanshu kumar Best Answer
The incorrect statement about the Cerium is only B option. B The +4 oxidation state of cerium is not known in solutions [ Incorrect ] As +4 oxidation state, is common for the Cerium. The correct statement about the Cerium are as follows: The common oxidation state of Cerium are +3, and +4. The +3 oxidation state of the Cerium is more stable than the +4 oxidation state. Cerium (IV) acts as an oxidising agent
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Option B is incorrect
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sir +4 oxidation state is more stable than+3 ???!
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no
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+3 is more stable
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sir ln ki common oxidation state +3 hoti h .....but cerium me stable oxidation state +4 hoti h na
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thn option c will also incorrect na ??
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sorry
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+3 is more stable for cerium
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only option B is incorrect
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ok sir
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Dinesh khalmaniya 1![best-answer]()
option A,C,D are correct For Cerium the +3 oxidation state is more stable than +4. The formation of Ce4+ is favoured by its noble gas configuration, but it is a strong oxidant reverting to the common +3 state. The Eo value for Ce4+/ Ce3+ is + 1.74 V which suggests that it can oxidise water.
sir +4 oxidation state is more stable than+3 ???!
The most common and stable oxidation state of Lanthanides is +3.It is attained by removing outermost 2 electrons of 6s electrons and 1 electron from 4f electrons. It is due to high energy difference in 4f and 6s, it is difficult to remove more electrons from 4f sub-shell.
lekin sir cerium k case me outer shell me 4 electrons hone k wajah se +4 will be more stable na ?
check this explanation