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Reshav posted an Question
April 28, 2021 • 18:21 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Ch,br ch,oh de is br 62. the correct order of sy2/ e2 ratio for the % yield of product of the following halide 154 ph (p) ch,ch,-c-ch, () ch,- ch-ch ch, ph (r)

CH,Br CH,OH de is Br 62. The correct order of Sy2/ E2 ratio for the % yield of product of the following halide 154 Ph (P) CH,CH,-C-CH, () CH,- CH-CH CH, Ph (R) CH-CH2 -I (S) CH,- CH-CH-CH, (d) Q>P>R>S (b) R>Q>S>P (c) P>R>S>Q (a) R>S>Q>P Tho maiar nraduct formed in the following reaction is

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  • Achyut ranjan gogoi best-answer

    option a is the answer as you have to see more the sn2 reaction and less the E2 type reaction gives the more yield which u can easily that R give faster sn2 than all and it will be highest yield product and p is the lowest due to low rate sn2. between Q and S u can see that e2 possibility in Q is good than S and hence its ratio is less.

  • Pinky chaudhary Chaudhary

    option b sn2 is inversely proportional to the stability of carbocation

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    its ans is given as a in booklet

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