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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Physics (PH)
Circular polariser
3 Answer(s)
Answer Now
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Ruby negi
option b is correct .. hope you now know the ans
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Abhishek singh
for positive z direction, the argument of exponential should have opposite signs for bothe kz and wt part. hence Option A or B could be answer. Now for circularly polarized light, their should be a phase difference of π/2 between x and y direction, which is shown by iota(i =√-1). hence Option B is correct. Best regards.
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Dhairya sharma
see whatever i attached. you will get an idea how to deal with it
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Dhairya sharma
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no need to remember
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Somnath
you can check it by calculation from x and y components of field.Suppose x component is Ex=Eo Sin(kz-wt) and y component is Ey=-EoSin(kz-wt).So you may write Ex+Ey=0.This is an equation of line.So wave is linearly polarised.Similarly Ex and Ey are such that you get Ex2+Ey2=Eo2 then since it is an equation of circle the wave will be circularly polarised.
thank you sir ..😊
welcome