Circular polariser

you can check it by calculation from x and y components of field.Suppose x component is Ex=Eo Sin(kz-wt) and y component is Ey=-EoSin(kz-wt).So you may write Ex+Ey=0.This is an equ...

option b is correct .. hope you now know the ans

for positive z direction, the argument of exponential should have opposite signs for bothe kz and wt part. hence Option A or B could be answer. Now for circularly polarized light, ...

see whatever i attached. you will get an idea how to deal with it

no need to remember

complete explanation. see attached.

Option B is correct. It is the equation for circularly polarized.