Shristy posted an Question
August 28, 2020 • 23:35 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Compare the equilibrium bond lengths of ab-type of diatomic molecules na no. o. ch and cn with their cations (ab ) and anions (ab). which of the following state

Compare the equilibrium bond lengths of AB-type of diatomic molecules Na NO. O. Ch and CN with their cations (AB ) and anions (AB). Which of the following statements is correct in general? (a) The equilibrium bond length of all AB' species will be shorter, and that of all AB species will be longer than that of the corresponding AB species. (b) The equilibrium bond length of all AB species will be shorter, and that of all AB" species will be longer than that of the corresponding AB species. (c) The equilibrium bond length of 0:. Ch'. CN ions will be shorter, than the corresponding neutral species. The equilibrium bond length of N2". NO" and Cl ions will be longer than the coresponding neutral species. (d) The equilibrium bond length of O,'. Clh, CN ions will be longer, than the corresponding neutral species. The equilibrium bond length of N:'. NO and Ch ions will be shorter than the corresponding neutral species. 3

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  • Suman Kumar Best Answer

    option C is correct

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    Draw Molecular orbital diagram. You will get all answer

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    One example I am explaining. Say O2 .

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    O2 has bond order 2 but O2+. has bond order 2.5

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    N2 has bond order 3 but N2+ has bond order 2.5

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    similarly you can solve all. Just you have to know MOD

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    Any doubt Shristy

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    ok mam I will try it

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    if you get any problem then ask

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    how to find the bond order greater than 20 electrons

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    Eg- Cl2 ??

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    Just like flourine

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    please mark the answer Shristy

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    but mam Cl2 me toh 34 electrons honge

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    and F2 me 18 electrons

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    so bond order dono ka same kaise niklega

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    Tumhe MOT sikhna padega. 20 eletron se jyda MOD complex hota. For simplicity treat it as flourine

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    so same as O and S also ??

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    yes

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