consider a double slit experiment with a light containg two wave length 450 mm andv600 mm .find the least order at which a maximum of one wavelength falls exactly on a minimum of the order
d sin(theta)=n* lamda1
d sin (theta)=(n+1)*lamda2
theta is same, as Maxima of one wavelength falls on the minima of second wavelength..
now,
using both equations, u get
n*600=(n+1...