S
Sudarshan Asked a Question April 10, 2020 12:16 pm
30 pts Consider a particle of m whose motion starts from rest in a constant gravitational field. If a resistive force, kmv, where v is the velocity, is encountered, the distance h the particle falls in accelerating from v, to v is given by (B) 2kg-kvi hS-kv (A)In 8+k g+kv (C)in+ky; (D)n k 8 +kv 2k 8-kv 2k
- 0 Likes
- 2 Comments
- Shares