Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Pradeep Jogsan posted an Question
April 23, 2021 • 05:59 am
![]()
30 points
30 points
- IIT JAM
- Physics (PH)
Consider free expansion of one mole of an ideal gas in an adiabatic container from volume v to v. the entropy change of the gas, calculated by considering a rev
Consider free expansion of one mole of an ideal gas in an adiabatic container from volume V to V. The entropy change of the gas, calculated by considering a reversible process between the original state (V,T) to the final state (V.T), where T is the temperature of the system is denoted by AS,. The corresponding change in the entropy of the surrounding is As,- Which of the following combinations is correct? () As = RIn(V,/V,). As, =-Rin (V, /V,) (b) AS= -R In (V,/V,). As, = RIn(V,/V,) () AS = RIn (V, /,), AS, =0 (d) AS,=-RIn (V, /V,), AS, =0
1 Answer(s)
Answer Now
- 0 Likes
- 3 Comments
- 0 Shares
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Som shekhar sharma
if we conclude this then option C is not suitable because universe is made of system and boundaries.
this is from jam 2011🙄
do you have any official solution.
no!
see in this problem we have given an Adiabatic container, now we see that process is reversible so total entropy of universe must be zero. and container expanding freely so no change in its internal energy. so change in entropy is due work done by the system. so we can calculate entropy cahnge of the system. hence we can get change in entropy of surroundings.