IIT JAM
Savia Asked a Question
September 15, 2020 8:34 pmpts 30 pts
  • IIT JAM
  • Biotechnology (BT)

(d) 1/18 if one of the diameters of a circle has end points (2, 0) and (4, 0), then the equation of that circle is x2- 3x + y2+ 5 = 0 (b)x4x + y+ 6 0 x 6x + y+

(D) 1/18 If one of the diameters of a circle has end points (2, 0) and (4, 0), then the equation of that circle IS x2- 3x + y2+ 5 = 0 (B)x4x + y+ 6 0 x 6x + y+ 8 = 0 (A) (C) -5x + y2 + 7 = 0 (D) JfD
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  • Deepak singh Best Answer
    see attached solution
    • cropped2752631901325289341.jpg
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  • Abhijeet Gaurav thankyou
    Answer is (D).
    • cropped1652515183499734011.jpg
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  • Deepak singh
    option d is correct
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