Nandani posted an Question
February 25, 2022 • 04:02 am 30 points
  • IIT JAM
  • Mathematics (MA)

(d) (4/3, 1, the system of equation kx+y +z = 1 x+ky +z =k and x+y +kz = k does not have a solution, if k is equal t0 (a) 0 (c)-1 (b)1 -2

(d) (4/3, 1, The system of equation kx+y +z = 1 x+ky +Z =k and x+y +kz = k does not have a solution, if k is equal t0 (a) 0 (c)-1 (b)1 -2

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