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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
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USP 7 electrostatics Q.8 M S Q I DIDN'T UNDERSTAND ANYTHING. HOW TO GET OPTIONS? Given solution is not enough to me to understand answer.
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Dr. manish kumar gupta![best-answer]()
we know that E = -dV/dr i.e. 'E' will be zero when 'V' is zero. option (A) is correct. after r=R, E is non zero, hence E(r-h) is not equal to E(r+h) at r=R. clearly, E is discontinuous at r=R option (B) is also correct. inside r=R, it is behaving like equipotential surface, hence no potential difference inside effectively no charge inside. outside r=R, it is behaving V is proportional to 1/r i.e. E is proportional to 1/(r)^2. clearly it's the curve for a hollow/metalic sphere. in both cases charge is avayonly at surface i.e. r=R., hence option (C) is also correct. clearly, outside r=R (or r>R), E is proportional to 1/(r)^2. So E will be zero only at r=infinite. so option (D) is wrong.