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Karnan posted an Question
November 06, 2020 • 21:03 pm 30 points
  • IIT JAM
  • Chemistry (CY)

(d) hc =c> ph,ch > phch, > c correct order of stability of free radcals (1-iv) 1s 1, (1) h2c=ch-ch2 (1) me,ch (i11) ph (v)ph-c (a) i>iv>ii> 1ii (b) iv>1> 111> 1

(d) HC =C> Ph,CH > PhCH, > C Correct order of stability of free radcals (1-IV) 1s 1, (1) H2C=CH-CH2 (1) Me,CH (I11) Ph (V)Ph-C (a) I>IV>II> 1II (b) IV>1> 111> 11 (c)IV>1|II>II dIV>1>11>11

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    Priyanshu kumar best-answer

    option D Explanation:- Triphenyl methyl free radical is most stable as the central radical carbon atom of the triphenylmethyl radical carries three phenyl groups. Therefore, the radical is highly resonance-stabilized. Phenyl radical is least stable as no resonance is possible in phenyl radical. An Allylic radical has an unpaired electron on an allylic carbon and, like an allylic cation, has two contributing resonance structures.

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    please ask if any doubt

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    given as b

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    Hyperconjugation dominance over resonanace...as allylic free radical have 2 resonating structure and secondary free radical has 7 hyperconjugative structure

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    Dinesh khalmaniya 1 best-answer

    option D. more the resonance more is the stability. here triphenyl methyl free radical is most stable because of resonance. I has less resonance than IV and II and III doesn't have any resonance.

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