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P. Dhivya posted an Question
October 18, 2020 • 00:29 am 30 points
  • IIT JAM
  • Physics (PH)

(d) no mg tration 1 0. two blocks of masses m 2 kg and m 5 kg are in contact on a frictionless table. a horizontal force f (-35 n) is applied to m. find the for

(d) No mg tration 1 0. Two blocks of masses m 2 kg and M 5 kg are in contact on a frictionless table. A horizontal force F (-35 N) is applied to m. Find the force of contact between the blocks. Will the force of contact remain same F if F is applied to M? tion As the blocks are rigid both will move with same acceleration under the action of a force F F 35 F ,N a = m m+ M 2+5 5 m/s2 Force of contact Ny Ma = 5 x 5 = 25 N If the force is applied to M then its action on m will be N m N=ma = 2 x 5 10 N. Note From this problem it is clear that acceleration does not depend on the fact that wheth- onliad M hut force gf contact does. m

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  • P. dhivya Palani

    but the contact force will remain the same right we consider only in that way in many problems

  • Surya prakash verma Best Answer

    since the table is frictionless both the block move as a system. acceleration of the system is 35/7=5 m/s^2 now look at the fbd of small block at both times. block of mass just need 10N force to move with acc. 5. so a negative contact force of 25N will have to act on it ,so that 35-25 results as 10N and the bigger block also gets 25N contact force, that make it move by acc 5. now look at the second scenario, bigger block need 25 N force so a contact force of 10 has to act so that the resultant on it is 35-10 which is 25. the same contact force in opposite direction a t on smaller block, i.e of 10 N which will accelerate it with 2

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    but how the contact force will remain different between two objects

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    but I think the contact force is same but the way they act may change am I right I am confused plz help

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    you can call me at 8618655402, may be then I can help u

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