Rajat Jain posted an Question
April 28, 2020 • 03:00 am 30 points
  • IIT JAM
  • Mathematics (MA)

(d) y(x)y(-x) is also a solution. let u(t) be a continuously differentiable function taking non-negative values for t> 0 and satisfying u'(t) = 4u" (t); u(0) =0

(D) y(x)y(-x) is also a solution. Let u(t) be a continuously differentiable function taking non-negative values for t> 0 and satisfying u'(t) = 4u" (t); u(0) =0. Then (A) u(t) = 0 (B) u(t) = t 0 for 0

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  • Priyadarshan Choursiya Best Answer

    see more

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    please explain option A.

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    here we assume that u=0 is solution then it satisfy DE and given that u=0 at t=0 so condition also satisfy. hence it is solution

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