Manisha posted an Question
December 01, 2020 • 16:04 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Dipole moment

I didn't get this order of Q4 & 5A, 5B...... actually OH is electro negative so in this case why arrow shows dipole from OH to benzene and not benzene to OH?

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    Priyanshu kumar Best Answer

    o-Nitrophenol will have lesser dipole moment than p-nitrophenol. This is because of resonance. During resonance, OH group will be electron donating group and will carry positive charge, where as nitro group is electron withdrawing group and carries negative charge. More is the charge separation, more is the dipole moment...Charge separation is more in para nitrophenol followed by meta nitrophenol and orthonitrophenol.

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    Decreasing dipole moment : CH3​Cl>CH2​Cl2​>CHCl3​>CCl4​.  The bond dipolesC−H and C−Clare in opposite direction.  In CH3​Cl, the resultant of  3C−H bond dipoles is reduced by one C-Cl bond dipole.  In CH2​Cl, the resultant 2C−H bond dipoles is reduced by the resultant 2 C-Cl bond dipoles. Hence, the dipole moment of CH2​Cl2​ is lower than the dipole moment of CH3​Cl. Similarly, CHCl3​ has lower dipole moment than In CH2​Cl2​, The net dipole moment of CCl4​ is zero because four C−Cl bond dipoles cancel each other.

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    got this?

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    No this 5A problem is not clear yet

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    which part?

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    How Dipole of CH2Cl2>CHCl3

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    in case of CHCl3, the three C-Cl bonds point to one side, so a moment equal to C-Cl bond is generated as a result. A moment of C-H bond is added to it. In CH2Cl2, the moment of two C-Cl bond points to one side

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    The resultant of 2 C-Cl bond and 2 C-H bond will be nearly in same direction which increases total dipole moment. However, in CHCl3 the resultant of 3 C-Cl bond makes some angle with C-H bond which relatively decreases total dipole moment.

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    owkay now i got it....

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    two Dipole (inside the plane and one outside the plane) is canceling the dipole of vertical Cl atom in case of CHCl3?

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