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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Priyanshu kumar Best Answer
In A order will be 2<1<3 and in b order will be 3<1<2 ...whats your doubt?
in a how 3 more stable than 1?
H is attached to sp hybridised carbon atom..so most acidic here
but after removing 1 H, there will be reso stablised na?
in 3 there is no reso
yes so 1 is more than 3 but here in 2 there is highest electronegativity so it readily release H+
i didnt get what you are saying sir
so i did numbering wrong so confusion...
what will be the answer
according to me for A, ans should be 2<3<1
Sourav 3 is most acidic as yha highest electronegativity hai so deprotonation bahut fast hoga then 1 reso stabilised then 2
Maine bola bhi koi rigid comparison nhi hota acidity or basicity decide krne me
but sir, reso stabilization jyda hota hai na electronegativity comparison se
yes you think is right...
im confused when to use what
sourav rigid nhi rhta hai khaskr acidity or basicity comparison me ....sometym pka or pkb differ...so confusion aate hai
but generally rule follow hote hai
sir ye stable kyun nahi hai
sir u there?
typing sourav🙂
According to me may be due to two factors as after deprotonation no resonance stabilised..and .after protonation oh2+ leaving group carbocation forms which is destabilized by - I effect of oxygen of och3 grp
it is saying that that molecule is unstable sir
if doing deprotonation and protonation, it is unstable, then the molecule shud be itself stable na
sourav unstable means it is reactive and och3 is good leaving group oh2+ is also good leaving grp...so it readily removes means reactive