Dy for y = f(x). if d2 = 0, = 0 at x = 0. and y = 1 at x =1. the value of y at x = 2 is_ dx

so , answer is 1...

since first and second derivative = 0 at x= 0 , it is possible only when y=f(x)= c (constant ) , also given that y = 1 at x= 1 this implies that y = f(x) = 1