Dy tslove the differential equation cot 3x-3y = cos 3x +sin 3x, 0

dy TSlove the differential equation cot 3x-3y = cos 3x +sin 3x, 0

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  Animesh anand

  kindly find your answer attach below

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  animesh ji aapne sin^3x ko kaise break kiya hai ?

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  yeh sin^2(3x) hai

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  cos2x=1-2sin^2(x) implies cos6x=1-2sin^2(3x)

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  can you tell me exactly where do you have problem ?(or which step )

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  samjh me aa gya

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  then you accept my answer

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