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###### Divya posted an Question
December 26, 2021 • 18:14 pm 30 points
• IIT JAM
• Physics (PH)

## Dy tslove the differential equation cot 3x-3y = cos 3x +sin 3x, 0 dy TSlove the differential equation cot 3x-3y = cos 3x +sin 3x, 0 1 Answer(s) Answer Now 0 Likes 1 Comments 0 Shares Likes Share Comments A Animesh anand kindly find your answer attach below Likes(0) Reply(6) animesh ji aapne sin^3x ko kaise break kiya hai ? Like(0) yeh sin^2(3x) hai Like(0) cos2x=1-2sin^2(x) implies cos6x=1-2sin^2(3x) Like(0) can you tell me exactly where do you have problem ?(or which step ) Like(0) samjh me aa gya Like(0) then you accept my answer Like(0) T

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