Divya posted an Question
December 26, 2021 • 18:14 pm 30 points
  • IIT JAM
  • Physics (PH)

Dy tslove the differential equation cot 3x-3y = cos 3x +sin 3x, 0

dy TSlove the differential equation cot 3x-3y = cos 3x +sin 3x, 0

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  • Animesh anand

    kindly find your answer attach below

    cropped1067309070722862446.jpg
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    animesh ji aapne sin^3x ko kaise break kiya hai ?

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    yeh sin^2(3x) hai

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    cos2x=1-2sin^2(x) implies cos6x=1-2sin^2(3x)

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    can you tell me exactly where do you have problem ?(or which step )

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    samjh me aa gya

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    then you accept my answer

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