Savia Asked a Question
September 4, 2020 12:03 pmpts 30 pts
e temperature of a calorimeter increases 0.10 K when 7.52J of electric energy is used to neat It. What is the heat capacity of the calorimeter? LDivii
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  • Ruby negi thankyou
    see solution...
    • cropped1725703400.jpg
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  • Anup padwal thankyou
    Given, Δt = increase or change in temperature= 0.10 K q= electric energy = 7.52J formula, C = q ÷ Δt Abswer= 75.2 J/K
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