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Prerna Chaudhary posted an Question
August 03, 2021 • 11:25 am 30 points
  • IIT JAM
  • Mathematics (MA)

Eduncle by raabe's test, 2 converges (for x= 1). for x> 1. hence the given series converges for x < 1 and diverges . 1.3 ... (4n -3) x 4n un2.4.. (4n -2) (i) 2n

Eduncle By Raabe's test, 2 Converges (for x= 1). for x> 1. Hence the given series converges for x < 1 and diverges ....... please check this and solve .I think it have some mistakes .

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  • Anuj s. best-answer

    un/un+1 = (4n-1)(4n+1)/(4n+2)(4n+4)x² un = (1.3.5....(4n-5)(4n-3))x²n/(2.4.6...(4n-2)(4n) un+1= (1.3.5....(4n-5)(4n-3)(4n+1))x²(n+1)/(2 .4.6....(4n-2)(4n)(4n+2)(4n+4)

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