Pooja Asked a Question
May 26, 2021 11:54 ampts 30 pts
Eduncle.com Physics (Solid State Pihysic 4.2 BCC (a) Plane (1 0 0) () No. of atoms 1 Gi) Area = a (ii) 1 Planar density = 1x m (58%) (iv) Packing fraction = 16r2 3 (b) Plane (1 1 0) No. of atoms = 2 (i) Area 2a2 (ii) Planar density = racking fraction =2x Tr 16r R83.59%) (iv) 2x 3 (C) Plane (1 1 1) [In BCC (1 1 1) will not contain body centered atom) (i) No. of atoms = 3a Area 2 (i) 1 ii) Planar density 3a? 3T (34% Tur Packing fraction2 s(4r2 2 3 (iv) 16 eco Hence (1 10) is closed pack plane in BCC. 4.3 FCC (a) Plane (1 0 0) ) No. of atoms =x 4 + 1 2 (i) Area = a 2 Planar density =2 (ii) 2x Tr Packing fraction = 4x2n?78.5%) (iv) 4 Website www.eduncle.comEna sUppori@eduncle.com Call Us 72319
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  • Mahak
    see attached
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  • Mahak thankyou
    see attached
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  • Mahak
    see attached
    • cropped5720594943038889172.jpg
    • cropped7679072846227917252.jpg
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  • Mahak
    see attached
    • cropped5720594943038889172.jpg
    • cropped7679072846227917252.jpg
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  • Pooja
    plss tell in this how to calculate volume 16r^2/3 in bcc and 2pii r^2 in FCC??
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