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Aditi Agrawal posted an Question
June 03, 2020 • 14:25 pm 30 points
  • IIT JAM
  • Physics (PH)

Eigen vectors.

the circled condition shows that k1 and k2 should not be equal to zero but when you have given example of matrix X then you have taken either k1 or k2 as zero.Why??

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    Abhishek singh Best Answer

    dear, k1 and k2 simultaneously couldn't be zero. but they can be zero one at a time.

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    the reason is, ..... if both simultaneously become zero, then all the three components of vector become zero. but Eigen vector could not be a zero vector. that's why we cannot take both simultaneously zero

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    can you please explain rubi Mam's comment . i didn't understand what is she trying to explain

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    you will either get her explanation in your notes after this topic or you will ask them as doubt. so it would be better for me and you as well to wait as of now. so ignore that comment as of now, because it looks you haven't reached that topic yet. so when you will read that, do ask.

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    Dhairya sharma best-answer

    dear if.....all will equal to 0 then we wont get any vector

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    Dhairya sharma

    from the vector which is eual to zero we get that k1 and k2 are -ve.no of eigen values is equal to no of linearly independent eigen values...

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    Ruby negi best-answer

    here when you have a same eigen values then you will first find the eigen vectors corresponding to eigen values and then corresponding to that eigen vector you have to find new eigen vector (using orthogonal property)..

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    can u please explain it by giving an example

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    example is in the copy that u r Reading... okay but give me some time

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    means among k1 and k2 any one value shold not be equal to zero .Do u want to say this??

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    both simultaneously should not be zero.

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    Ruby negi

    yeah,no of distinct eigen values is equal to no of linearly independent eigen values...

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    i understood this but my question is that if we have to take k1 and k2 as not equal to zero then in example for matrix X why the value is taken as zero for either k1 or k2

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