Anand posted an Question
January 18, 2021 • 23:59 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Equivalent weight of k2cr2:07 in acidic medium will be: (atomic weight of k 39, cr 52 and o= 16) (a) 294/2 b) 294/3 (c) 294/ 6 t g31 (d) 294

Equivalent weight of K2Cr2:07 in acidic medium will be: (Atomic weight of K 39, Cr 52 and O= 16) (a) 294/2 b) 294/3 (c) 294/ 6 t G31 (d) 294

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    Priyanshu kumar Best Answer

    option C

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    how to find ans of such que in acidic and basic media

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    you have to keep in mind idea about reactions in both acidic and basic media

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    Check no of electron gained or lost and divide it by molecular weight...you get equivalent weight

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    for basic

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    balance reaction in acidic and basic medium...which you read in 11th balancing the redox reaction

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    I think in basic medium n factor is 3

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