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Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
Chandan Panigrahi posted an Question
October 02, 2020 • 03:04 am
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30 points
30 points
- IIT JAM
- Chemistry (CY)
Ex. the emf of the cell, pb | pbcl, || agci | ag at 300 k is 0.50 v. if the temperature emf is-2 x 104 volt deg-1, calculate ah and as for the cell reaction, pp
Ex. The EMF of the cell, Pb | PbCl, || AgCI | Ag at 300 K is 0.50 V. If the temperature EMF is-2 x 104 volt deg-1, calculate AH and AS for the cell reaction, ppp coetficien ec Pb + 2AgCl PbC, + 2Ag Pb PbCL|CH | AgCl | Ag iff- Sol. The cell reaction is Pb + 2AgCl > PbCl, + 2Ag AG =- nFE = -2 x 96500 x 0.5 J =-96,500 J or -96.5 kJ AS =n FE OT = 2x 96500 (-2 x 104) =-38.6 JK1 AG AH-TAS, -96,500 AH 300 (-38.6) AH -96,500 300x 38.6 = -108,080 J or 108.08 kJ sir in this question how it takes E=0.5j as it is given that E=0.50v
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Dinesh khalmaniya 1
what's your doubt?
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here it takes E=0.5j but in the question its given that E=0.50v
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we can take here 1 joue to 1 volt
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EMF is commonly measured in units of volts, equivalent in the metre–kilogram–second system to one joule per coulomb of electric charge. In the electrostatic units of the centimetre–gram–second system, the unit of electromotive force is the statvolt, or one erg per electrostatic unit of charge.
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Priyanshu kumar![best-answer]()
electromotive force is not actually a force. It is commonly measured in units of volts, equivalent in the metre–kilogram–second system to one joule per coulomb of electric charge.
So here it is taken