Simun Mishra posted an Question
June 27, 2020 • 16:32 pm 30 points
  • IIT JAM
  • Chemistry (CY)

Explain it pls

3 Answer(s) Answer Now
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    Dinesh khalmaniya 1 best-answer

    Two stereoisomers that are mirror images are enantiomers.  The prefix enantio- designates the mirror-image relationship. Two stereoisomers of the same compound that are not enantiomers are diastereomers.  This is a fairly broad definition, as we'll see. When comparing two molecules to find their relationship, the "decision tree" goes as such: Are they, in fact, stereoisomers?  The connectivity must be identical, otherwise they are constitutional isomers and not stereoisomers.  An example would be butane vs. 2-methylpropane. Are they identical?  (Check to make sure!  This can trip you up if you aren't careful.)  If they are truly stereoisomers and not identical, then they must be either enantiomers or diastereomers.  You may need to reorient one of them to see--or you may need to rotate about single bonds, or do cyclohexane ring flips in order to see if they are simply different conformers of the same molecule. Are they mirror images of each other?  If yes, they are enantiomers.  The caution about reorienting and looking at other conformations is important. If you get to this point--they are stereoisomers and they are not enantiomers, then they are diastereomers.

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    Boddu rama krishna best-answer

    Two compounds with the exact same connectivity, that are mirror images of each other but that are not identical to each other are called enantiomers. The more common definition of an enantiomer is that it is not superimposable on its mirror image. It can be distinguished easily from its mirror image, just as a right hand can easily be identified and distinguished from a left hand.

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    only option B is correct

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    Priyanshu kumar

    hope you understand simun??

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    dash convert to wedge and wedge convert to dash in mirror image ..?

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    Priyanshu kumar

    option B is right see as enantiomers is non superimposable on their mirror images...In 1st 3rd and 4th option these pairs are not mirror images to each other...so correct option is 2

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