30 points
>
>
Time management is very much important in IIT JAM. The eduncle test series for IIT JAM Mathematical Statistics helped me a lot in this portion. I am very thankful to the test series I bought from eduncle.
Nilanjan Bhowmick AIR 3, CSIR NET (Earth Science)
- IIT JAM
- Chemistry (CY)
Explain it with reason
Tucture. (b) H,O, ) S,Cl, td) H,C Assuming pure 2s and 2p orbitals of carbon are used in forming CH, molecule, which of the following statement is false ? (a) Four C-H bonds will be at 90°. a(bThree C-H bond will be stronger than 4th C-H bond. c) The angle of C-H bond formed by s-s overlapping will be uncertain with respect to other three bonds. (d) No prediction regarding the shape of the molecule. Match the following:
1 Answer(s)
Answer Now
- 0 Likes
- 7 Comments
- 0 Shares
-
Suman Kumar Best Answer
Option A will be the answer Reshav.
![eduncle-logo-app]()
Please ask if you don't get anything 🙏
![eduncle-logo-app]()
yes this option is correct but please give me reason for thus
![eduncle-logo-app]()
Reshav p orbital how do they orient in space.
![eduncle-logo-app]()
You tell me
![eduncle-logo-app]()
Three p orient themselves in 90⁰ with each other. Px, Py, Pz.
![eduncle-logo-app]()
Now in question it is given pure 2p & pure 2s is used.
![eduncle-logo-app]()
Since S is spherical so you can't define bond angle for one C-H bond. But for remaining 3p since they are 90⁰ with respect to each. Three C-H bond angle will be 90⁰
![eduncle-logo-app]()
Still not clear please ask again where you can not understand.
-
![comment-profile-img]()
>
-
![comment-profile-img]()
>
Dinesh khalmaniya 1
CH4 has tetrahederal structure orientation with sp3 hybridization. hece 4 C-H bonds would be at equal angles with each C-H bond. and that would be 109.5 degree and that is practically observed. And all would have same strength as all are identical.
![eduncle-logo-app]()
got it??
![eduncle-logo-app]()
check it also
-
![comment-profile-img]()
>
Priyanshu kumar
hope this will help u reshav😊🙏
-
![comment-profile-img]()
>
Priyanshu kumar
In methane that is CH4, the hybridisation of the central carbon atom is sp3. Therefore the geometry of the atom is tetrahedral.Now that means that the C-H bonds will form an angle of 109o28' with each other. As all the positions are equivalent in a CH4 molecule therefore the bp-bp repulsions will be minimum when the angle is 109o28'(by VSEPR Theory). now your question is assuming pure 2s and 2p orbitals are involved in bonding.therefore 3 C-H bonds will be at right angles but one will be indefinite.3 C-H bonds will be identical but one will be not. The angle formed by s-s overlapping will be undefined.
![eduncle-logo-app]()
https://youtu.be/18sl2FIvXq8 check this video...it helps
![eduncle-logo-app]()
reshav got it or any doubt then ask??
Do You Want Better RANK in Your Exam?
Start Your Preparations with Eduncle’s FREE Study Material
- Updated Syllabus, Paper Pattern & Full Exam Details
- Sample Theory of Most Important Topic
- Model Test Paper with Detailed Solutions
- Last 5 Years Question Papers & Answers
Sign Up to Download FREE Study Material Worth Rs. 500/-
Suman Kumar
Hope you like the answer 🙏