Shib Sagar posted an Question
July 20, 2020 • 00:23 am 30 points
  • IIT JAM
  • Chemistry (CY)

Explain the answers

Whie h of the tollowimg proe @ss is oscO Ccted is Cuith beshh

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    Priyanshu kumar best-answer

    shib for ques 10 the correct option is option C..as the chlorine has more tendency to accept electrons...so its electron affinity value is more negative,more energy release, the first option is the case of ionisation enthalpy which is endothermic(energy needed),the 2nd option is the case of 2nd electron gain enthalpy of oxygen which is positive and the 4th option is the case of electron affinity but its value is less negative than value of chlorine..So correct option is option C

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    check this shib..it helps😊🙏

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    shib please check it...

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    Priyanshu kumar best-answer

    for ques no 14...as you know shib ionisation enthalpy whether first second,third etc is always positive means endothermic, ...the case arises for 2nd electron gain enthalpy which is always positive that is endothermic...the first electron gain enthalpy is always exothermic but for noble gases it has zero or positive value...so considering this you can say first electron gain enthalpy has tendency to show both endothermic and endothermic....

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    for ques 18...as you know second IP is the energy needed to remove a second electron from each ion in 1 mole of gaseous 1+ ions to give gaseous 2+ ions.so check after removal of one electron which compound has more stable structure...those which have more stable structure then they have more second IP..your configuration is not clear...so check on this concept...it helps

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    please accept the answer if it helps😊🙏

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