Muskan trivedi 1 Asked a Question
July 4, 2022 10:21 ampts 30 pts
fA is the threshold wavelength for photoelectric emission, A wavelength of light falling on the Surface of metal, and m, mass of electron, then de Broglie wavelength of emitted electron is h02) 2mc(-) hOg-) (6)2mcAo hO-A,) 2mco /52 2mc
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  • Bhagat singh 1 Best Answer
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