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Vijay posted an Question
February 22, 2021 • 15:32 pm 30 points
  • IIT JAM
  • Mathematics (MA)

Fais constant vector then grad .a) = (a) b)a ()0 (d) af o a ob oc o d iff = xyi +2x yzj-3yz?k then the value of curlf at point (1, -1, 1) is (a)i+2k ) -i-2k ) n

fais constant vector then grad .a) = (a) b)a ()0 (d) af O a Ob Oc O d IfF = xyi +2x yzj-3yz?k then the value of curlF at point (1, -1, 1) is (a)i+2k ) -i-2k ) none of these O a O b O C O d

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