Find out the relative acidic strength of

We know that carboxylic acid is most stable due to equivalent resonating structures of conjugate base. So it most acidic, Now structure (1) is less acidic than (3) because Conjugate Base is less stable. Structure (1) is mose stable than (2) and (4) because Conjugate Base of structure gives amine which is stabilised by +I effect of Methyl group. So structure (1) is more acidic than structure (2) and (4),  structure (4) is more acidic than (2) due to the more electronegativity of O atom than C atom.

Based on pka value Pka values of Ch3Nh3+ =10.7, propyne =25, acetic acid=4.75 ,methanol=15.5.... less is the pka values,more is the acidity.. so also the correct order is acetic acid> methylammonium ion>methanol>propyne i.e 3>1>4>2

please mark this answer too if you got it mansi😊

Dear student, Correct answer is CH4 < NH3 < H2O < HF. Acidic strength increases as the electronegativity of central atom increases. Electronegativity is in the order C < N < O < F. Or we can understand it in different way- Acids are the one which losses H+ ions and will form its conjugate base. More stable a conjugate base of an acid more strong the acid is i.e. it easily losses its H+ ion to form stable conjugate base. HF conjugate base (C.B.) is F- , H2O C.B. is OH- , NH3 C.B. is NH2- , CH4 C.B. is CH3-. Stability order of these C.B. are ​F- > OH- > ​NH2- > ​CH3- .

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yess, thankyou

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